Answers 0 Sign in to vote Hi DrewT1755 I use expression in my environment, it will return correct day =Datediff ("d",Fields!datetime1.Value,Fields!datetime2.Value) My data type are all datatime and textbox properties->Number->default, please check your data type and whether you set other thing in textbox properties Best Regards, Zoe Zhi MSDN Community Support
In Reporting Services, DateDiff function is used to return a long value specifying the number of time intervals between two date values. DatePart function is used to return an integer value containing the specified component of a given Date value. The examples below are for your references:
Answers 0 Sign in to vote D = datetime you want to convert, ex. "02-07-2012 2:25:01 PM" JD = Julian Date JT = Julian Time JD = (DATEPART (year,D)-1900)*1000+DATEDIFF ...
First of all, the definition of "week" is a non-trivial matter. Does your week start on Mondays or Sundays? If Oct 1 is on a Saturday, what is week 1? Here is a fairly simple-minded solution: SELECTdatediff (wk, convert (char (6), datecol, 112) + '01', datecol) + 1 Erland Sommarskog, SQL Server MVP, [email protected] Proposed as answer byNaomi NTuesday, November 22, 2011 1:43 AM Marked as ...
Then you will select the DateDiff values of each date and you will select the date from the tbl2 list that has the smallest DateDiff value (the closest date to 1/30/2013) The queries would look something like this: (note Day is a reserved word -- need to name it differently) Select validFrom into tmp1 from tbl2 Where validfrom < '1/30/2013)
I see several examples of converting Julian Dates, but not a simple one that's escaping me. Can someone provide the formula to convert today to today's 3-digit Julian date? Thursday, September 12, 2019 4:42 PM
Hi I hope someone can help with this. I am trying to execute a stored procedure which has four parameters, all of which are null by default. I'm pretty new with Entity framework and found this very straight forward before with ado.net, but am persisting with EF. My issue is that whatever I set the parameters to it always ends up running the stored procedure with the default null values. my code:
